This blog post will teach you how to convert an array of integers into a scalar index. This is useful for creating arrays with multiple dimensions, or when the size of the input array is unknown.
In order to convert an integer array into a scalar index, we need to iterate through each item in the array and find its position in relation to the beginning of the list. Once we have that number, we can use it as our new starting point- this way, our output will be one dimension shorter than the input!
Convert an Array of Integers into a Scalar Index
We’ll use a for loop to iterate through the items in our input array. The first line of code will assign the current index (position) as well as an output variable, so that we can keep track of what number represents which item within the list:
input = [60, 61, 62];
var position = 0;
var newPosition = null;
The second line is where we actually do the conversion work by using two nested loops: one to find out how many integers are left after this iteration and another to compare it with our desired size. If you’re converting from scalar arrays into a scalar index, your target size should be equal or greater than the original dimensions!
for (var i = 0; i <= input.length
(input[i] === null || typeof input[i] !== ‘number’); ++i) { …. } first loop iterates through all the integers in our list except the last one, checking if they’re scalars or not and assigning them to a new variable called “index” which is incremented by one each time because it’s an array index that we are cycling over var index = []; second nested loop cycles only through those numbers that were found as scalar values from the previous iteration of this inner loop while (!Number.isNaN(newPosition)) { if (typeof position >=”undefined”) { index.push(position); } newPosition = position; ++index[i];; // to populate the second array, we iterate through the first one while checking if each element is a scalar value or not
this loop will cycle over all of our values in “array” and assign them as an object to “object” for (var i=0; i <= input.length This inner nested loop checks that only integers are being placed into object by incrementing their counter with every iteration until they exceed the length limit which prevents any numbers other than integers from being added var objObject = [];
The following code checks for booleans, and if they are not present in the given array, it will add them to object. If boolean values exist within an array that is being converted into a scalar index then those booles should be excluded from the conversion process else their values would overwrite any value already set (index[i] = typeof input[i] === “boolean” ? false : true;) }
In the current example, we are converting an array of integers into a scalar index. TypeError is thrown when any type other than integer or boolean arrays are used to create this conversion. This can be fixed by changing the input values to either booleans or numbers in order for them to be converted properly. The following code checks for booleans and if they exist then it will exclude their value from being set as part of the new scalar index (index[i] = typeof input[i] === “boolean” ? false : true;) – however if there are no Boolean types present in the given array, but instead only contains numeric data, then those values would overwrite any that were already set previously due to the typeof input === “number” check. This can be fixed by changing that to typeof input === “boolean” || typeof input == ‘number’ in order for it to work properly without any data loss.
